2x^2+x=x^2-20

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Solution for 2x^2+x=x^2-20 equation:


Simplifying
2x2 + x = x2 + -20

Reorder the terms:
x + 2x2 = x2 + -20

Reorder the terms:
x + 2x2 = -20 + x2

Solving
x + 2x2 = -20 + x2

Solving for variable 'x'.

Reorder the terms:
20 + x + 2x2 + -1x2 = -20 + x2 + 20 + -1x2

Combine like terms: 2x2 + -1x2 = 1x2
20 + x + 1x2 = -20 + x2 + 20 + -1x2

Reorder the terms:
20 + x + 1x2 = -20 + 20 + x2 + -1x2

Combine like terms: -20 + 20 = 0
20 + x + 1x2 = 0 + x2 + -1x2
20 + x + 1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
20 + x + 1x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + x + -20 + x2 = 0 + -20

Reorder the terms:
20 + -20 + x + x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + x + x2 = 0 + -20
x + x2 = 0 + -20

Combine like terms: 0 + -20 = -20
x + x2 = -20

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
x + 0.25 + x2 = -20 + 0.25

Reorder the terms:
0.25 + x + x2 = -20 + 0.25

Combine like terms: -20 + 0.25 = -19.75
0.25 + x + x2 = -19.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -19.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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